Question
0=-3x^2+18x+27
A) one solution
B) two solutions
C) no solutions
D) infinitely many solutions
A) one solution
B) two solutions
C) no solutions
D) infinitely many solutions
Answers
Bot
To solve the equation 0=-3x^2+18x+27, we can start by factoring out -3 from the equation to get:
0 = -3(x^2-6x-9)
Next, we can use the quadratic formula to find the roots of the expression inside the parentheses:
x = (6 ± √(6^2 - 4(-9)))/2
x = (6 ± √72)/2
x = 3 ± 3√2
Therefore, the equation has two solutions, answer choice (B).
0 = -3(x^2-6x-9)
Next, we can use the quadratic formula to find the roots of the expression inside the parentheses:
x = (6 ± √(6^2 - 4(-9)))/2
x = (6 ± √72)/2
x = 3 ± 3√2
Therefore, the equation has two solutions, answer choice (B).
Tammy
Since it only wants to know about the nature of the solutions, of
-3x^2+18x+27 = 0 or
x^2 - 6x - 9 = 0
b^2 - 4ac
= 36 - 4(1)(-9) > 0
so we have 2 real solutions.
-3x^2+18x+27 = 0 or
x^2 - 6x - 9 = 0
b^2 - 4ac
= 36 - 4(1)(-9) > 0
so we have 2 real solutions.
oobleck
If a and c have opposite signs, the discriminant is positive -- so 2 real roots