Asked by Branny
                The path of a particle moving in a straight line is given by s=t³-6t²+9t+4 find s and a when v=0
            
            
        Answers
                    Answered by
            Damon
            
    ds/dt = v = 3 t^2 - 12 t + 9
d^2s/dt^2 = 6 t - 12 = a
when v = 0
3 t^2 - 12 t + 9 = 0
t^2 - 4 t + 3 = 0
(t - 3) (t-1) = 0
so
when t = 1 and when t = 3 , v = 0
when t = 1
s = 1 - 6 + 9 + 4 = 8
a = 6 - 12 = -6
when t = 3
s = 27 - 54 + 27 + 4 = 4
a = 18-12 = 6
    
d^2s/dt^2 = 6 t - 12 = a
when v = 0
3 t^2 - 12 t + 9 = 0
t^2 - 4 t + 3 = 0
(t - 3) (t-1) = 0
so
when t = 1 and when t = 3 , v = 0
when t = 1
s = 1 - 6 + 9 + 4 = 8
a = 6 - 12 = -6
when t = 3
s = 27 - 54 + 27 + 4 = 4
a = 18-12 = 6
                                                    There are no AI answers yet. The ability to request AI answers is coming soon!
                                            
                Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.