Asked by bethany
What is the value of ab if the lines 2x+ay=6 and by=6x-9 are perpendicular? (I understand they are negative reciprocals, so 'a' times 'b' is -1, just not sure what to do from here)
Answers
Answered by
Damon
a y = - 2 x + 6 , y = -2/a x + 6/a
slope1 = -2/a
y = 6/b - 9/b
slope2 = 6/b
slope2 = -1/slope1
6/b = -1/ (-2/a) = 2/a
6 a = 2 b
b = 3 a
a b = 3 a^2
slope1 = -2/a
y = 6/b - 9/b
slope2 = 6/b
slope2 = -1/slope1
6/b = -1/ (-2/a) = 2/a
6 a = 2 b
b = 3 a
a b = 3 a^2
Answered by
oobleck
oops.
6/b = -1/ (-2/a) = 2/a
should be
6/b = -1/ (-2/a) = a/2
so ab = 12
6/b = -1/ (-2/a) = 2/a
should be
6/b = -1/ (-2/a) = a/2
so ab = 12
Answered by
Damon
Tilt !
Thank you oobleck !
Thank you oobleck !
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.