We can use the formula for the nth term of an arithmetic progression:
a_n = a_1 + (n-1)d
Where a_1 is the first term, d is the common difference, and n is the term number.
Using the given information:
a_2 = x-2
a_3 = 5
a_4 = x+2
We can find the common difference, d, by subtracting a_2 from a_3, or by subtracting a_3 from a_4:
d = a_3 - a_2 = 5 - (x-2) = 7-x
d = a_4 - a_3 = (x+2) - 5 = x-3
Setting these expressions equal to each other:
7-x = x-3
Solving for x:
2x = 10
x = 5
Therefore, the value of x is 5.
The 2nd 3rd and 4th term of an aritmetic progression
are x-2, 5 and x+2 respectively. Find x
2 answers
To make a long story short:
To be in an AS,
5 - (x-2) = x+2 - 5
5 - x + 2 = x + 2 - 5
-2x = -10
x = 5
To be in an AS,
5 - (x-2) = x+2 - 5
5 - x + 2 = x + 2 - 5
-2x = -10
x = 5