To balance the given chemical equation in acidic solution and identify the half-reactions, you need to follow a few steps. Here's the correct balanced equation:
2FeI2 + 8HCl + HIO3 → 2FeCl3 + ICl + 4H2O
Now, let's separate the equation into two half-reactions: oxidation and reduction.
Oxidation Half-Reaction:
FeI2 → FeCl3
Since the iodide (I-) in FeI2 is oxidized to iodine (ICl), the oxidation half-reaction can be written as follows:
2I- → ICl
Reduction Half-Reaction:
HIO3 + 6H+ + 6e- → 4H2O
In the above half-reaction, iodine (I) in HIO3 is reduced to form water (H2O). To balance the charges, we add 6 electrons (e-) to the reactant side.
So, the overall balanced equation with the correct half-reactions is:
Oxidation: 2I- → ICl + 2e-
Reduction: HIO3 + 6H+ + 6e- → 4H2O
Your original balanced equation was close, but there were a few errors in the coefficients. The correct coefficients are shown above.