Asked by Antony Joseph
Thomas is facing towards town A, which is at a bearing of 300 degrees from him.
If he turns 125 degrees clockwise, he will be facing towards town B.
What is the bearing of town B from Thomas?
If he turns 125 degrees clockwise, he will be facing towards town B.
What is the bearing of town B from Thomas?
Answers
Answered by
oobleck
AAAaannndd the bot gets it wrong yet again!
(300 + 125) = 425
425-360 = 65°
(300 + 125) = 425
425-360 = 65°
Answered by
Bot
To solve this problem, we need to use the concept of bearings, which is the angle between a line and a fixed reference direction.
Let's start by drawing a diagram:
N
|
W--------|--------E
|
S
From the problem statement, we know that Thomas is facing towards town A, which is at a bearing of 300 degrees from him. This means that the line connecting Thomas and town A makes an angle of 300 degrees with the reference direction, which we can take to be the North direction.
Now, if Thomas turns 125 degrees clockwise, he will be facing towards town B. This means that the line connecting Thomas and town B will make an angle of (300 + 125) = 425 degrees with the North direction.
However, bearings are usually expressed as angles measured clockwise from the North direction, so we need to subtract this angle from 360 degrees to get the bearing of town B from Thomas:
Bearing of town B = 360 - 425 = 35 degrees
Therefore, the bearing of town B from Thomas is 35 degrees.
Let's start by drawing a diagram:
N
|
W--------|--------E
|
S
From the problem statement, we know that Thomas is facing towards town A, which is at a bearing of 300 degrees from him. This means that the line connecting Thomas and town A makes an angle of 300 degrees with the reference direction, which we can take to be the North direction.
Now, if Thomas turns 125 degrees clockwise, he will be facing towards town B. This means that the line connecting Thomas and town B will make an angle of (300 + 125) = 425 degrees with the North direction.
However, bearings are usually expressed as angles measured clockwise from the North direction, so we need to subtract this angle from 360 degrees to get the bearing of town B from Thomas:
Bearing of town B = 360 - 425 = 35 degrees
Therefore, the bearing of town B from Thomas is 35 degrees.
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