We can use the formula for the area of a regular octagon:
A = 2(1 + √2) × s^2
where s is the length of a side of the octagon.
Substituting s = 6 cm, we get:
A = 2(1 + √2) × 6^2
A = 2(1 + 1.414) × 36
A = 2(2.414) × 36
A = 173.8 cm^2 (rounded to the nearest tenth)
Therefore, the answer is d) 173.8 cm^2.
find the area of a regular octogon with side length 6 cm to the nearest tenth a 29.8 cm^2
b 38 cm^2
c 77.9 cm^2
d 173.8 cm^2
1 answer