Asked by Rachael
What is the percentage by mass of hydrogen in ethanoic acid?
Answers
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The chemical formula of ethanoic acid is CH3COOH. It contains two atoms of hydrogen in each molecule. The atomic weight of hydrogen is 1.008 g/mol, and the molecular weight of ethanoic acid is 60.05 g/mol.
Therefore, the percentage by mass of hydrogen in ethanoic acid can be calculated as follows:
Mass of hydrogen = 2 x 1.008 g/mol = 2.016 g/mol
Mass of ethanoic acid = 60.05 g/mol
Percentage by mass of hydrogen = (mass of hydrogen / mass of ethanoic acid) x 100
= (2.016 g/mol / 60.05 g/mol) x 100
= 3.36%
Therefore, the percentage by mass of hydrogen in ethanoic acid is 3.36%.
Therefore, the percentage by mass of hydrogen in ethanoic acid can be calculated as follows:
Mass of hydrogen = 2 x 1.008 g/mol = 2.016 g/mol
Mass of ethanoic acid = 60.05 g/mol
Percentage by mass of hydrogen = (mass of hydrogen / mass of ethanoic acid) x 100
= (2.016 g/mol / 60.05 g/mol) x 100
= 3.36%
Therefore, the percentage by mass of hydrogen in ethanoic acid is 3.36%.
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