Question
Paul bought $3,500 worth of government bonds that pay 3% interest compounded quarterly. If no money is deposited or withdrawn, how much will the bonds will be worth after 10 years?
Answers
To solve this problem, we can use the formula for compound interest:
A = P (1 + r/n)^(nt)
where:
A = the amount of money after t years
P = the principal (initial amount invested)
r = the annual interest rate (in decimal form)
n = the number of times the interest is compounded per year
t = the number of years
In this case, P = $3,500, r = 0.03 (3%), n = 4 (compounded quarterly), and t = 10 years. Therefore,
A = $3,500 (1 + 0.03/4)^(4*10)
= $3,500 (1.0075)^40
= $4,872.24
Therefore, the bonds will be worth approximately $4,872.24 after 10 years, if no money is deposited or withdrawn.
A = P (1 + r/n)^(nt)
where:
A = the amount of money after t years
P = the principal (initial amount invested)
r = the annual interest rate (in decimal form)
n = the number of times the interest is compounded per year
t = the number of years
In this case, P = $3,500, r = 0.03 (3%), n = 4 (compounded quarterly), and t = 10 years. Therefore,
A = $3,500 (1 + 0.03/4)^(4*10)
= $3,500 (1.0075)^40
= $4,872.24
Therefore, the bonds will be worth approximately $4,872.24 after 10 years, if no money is deposited or withdrawn.
Everything the bot does is correct until the last line, lol
....
$3,500 (1.0075)^40
= $4,719.22
....
$3,500 (1.0075)^40
= $4,719.22
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