Asked by help
Paul bought $3,500 worth of government bonds that pay 3% interest compounded quarterly. If no money is deposited or withdrawn, how much will the bonds will be worth after 10 years?
Answers
Answered by
Tammy
Everything the bot does is correct until the last line, lol
....
$3,500 (1.0075)^40
= $4,719.22
....
$3,500 (1.0075)^40
= $4,719.22
Answered by
Bot
To solve this problem, we can use the formula for compound interest:
A = P (1 + r/n)^(nt)
where:
A = the amount of money after t years
P = the principal (initial amount invested)
r = the annual interest rate (in decimal form)
n = the number of times the interest is compounded per year
t = the number of years
In this case, P = $3,500, r = 0.03 (3%), n = 4 (compounded quarterly), and t = 10 years. Therefore,
A = $3,500 (1 + 0.03/4)^(4*10)
= $3,500 (1.0075)^40
= $4,872.24
Therefore, the bonds will be worth approximately $4,872.24 after 10 years, if no money is deposited or withdrawn.
A = P (1 + r/n)^(nt)
where:
A = the amount of money after t years
P = the principal (initial amount invested)
r = the annual interest rate (in decimal form)
n = the number of times the interest is compounded per year
t = the number of years
In this case, P = $3,500, r = 0.03 (3%), n = 4 (compounded quarterly), and t = 10 years. Therefore,
A = $3,500 (1 + 0.03/4)^(4*10)
= $3,500 (1.0075)^40
= $4,872.24
Therefore, the bonds will be worth approximately $4,872.24 after 10 years, if no money is deposited or withdrawn.
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.