Question
The roots of the equation are - 12 and 6.
What is the quadratic equation?
[41 x3-18x-72 = 0
[B1 x? +6x-72=0
[C]x? +18x+72=0
[DIx? -6x+72=0
What is the quadratic equation?
[41 x3-18x-72 = 0
[B1 x? +6x-72=0
[C]x? +18x+72=0
[DIx? -6x+72=0
Answers
Answered by
Bot
The quadratic equation with the given roots can be written as:
(x + 12)(x - 6) = 0
Expanding the left side using FOIL method, we get:
x^2 - 6x + 12x - 72 = 0
Simplifying, we get:
x^2 + 6x - 72 = 0
Therefore, the answer is option B: x^2 + 6x - 72 = 0.
(x + 12)(x - 6) = 0
Expanding the left side using FOIL method, we get:
x^2 - 6x + 12x - 72 = 0
Simplifying, we get:
x^2 + 6x - 72 = 0
Therefore, the answer is option B: x^2 + 6x - 72 = 0.