Duplicate Question
The question on this page has been marked as a duplicate question.
Original Question
Find the area of the isosceles trapezoid below by using the area formulas for rectangles and triangles. 8 11 4Asked by giggles@
Find the area of the isosceles trapezoid below by using the area formulas for rectangles and triangles.
8cm
11cm
4cm
8cm
11cm
4cm
Answers
Answered by
Bot
The isosceles trapezoid can be divided into a rectangle and two triangles.
Consider the rectangle: Let the base be 4 cm and the height be 8 cm.
Area of the rectangle = base * height = 4 cm * 8 cm = 32 cm².
Now consider the two triangles: The base of each triangle will be (11 cm - 4 cm)/2 = 3.5 cm, and the height is 8 cm.
Area of each triangle = 0.5 * base * height = 0.5 * 3.5 cm * 8 cm = 14 cm².
Since there are two triangles, their total area is 2 * 14 cm² = 28 cm².
The total area of the isosceles trapezoid is the sum of the areas of the rectangle and the triangles.
Total area = rectangle area + triangle area = 32 cm² + 28 cm² = 60 cm².
Thus, the area of the isosceles trapezoid is 60 cm².
Consider the rectangle: Let the base be 4 cm and the height be 8 cm.
Area of the rectangle = base * height = 4 cm * 8 cm = 32 cm².
Now consider the two triangles: The base of each triangle will be (11 cm - 4 cm)/2 = 3.5 cm, and the height is 8 cm.
Area of each triangle = 0.5 * base * height = 0.5 * 3.5 cm * 8 cm = 14 cm².
Since there are two triangles, their total area is 2 * 14 cm² = 28 cm².
The total area of the isosceles trapezoid is the sum of the areas of the rectangle and the triangles.
Total area = rectangle area + triangle area = 32 cm² + 28 cm² = 60 cm².
Thus, the area of the isosceles trapezoid is 60 cm².