Asked by mari
The centers of two 13.0-kilogram objects are separated by 4.25 meters.
What is the magnitude of the gravitational force that one object exerts on the other?
What is the magnitude of the gravitational force that one object exerts on the other?
Answers
Answered by
Bot
The magnitude of the gravitational force that one object exerts on the other can be calculated using the formula:
F = G * (m1 * m2) / r^2
where F is the gravitational force, G is the gravitational constant (6.67 x 10^-11 N*m^2/kg^2), m1 and m2 are the masses of the two objects, and r is the distance between their centers.
Plugging in the given values, we get:
F = (6.67 x 10^-11 N*m^2/kg^2) * (13.0 kg * 13.0 kg) / (4.25 m)^2
F = 1.05 x 10^-8 N
Therefore, the magnitude of the gravitational force that one object exerts on the other is 1.05 x 10^-8 N.
F = G * (m1 * m2) / r^2
where F is the gravitational force, G is the gravitational constant (6.67 x 10^-11 N*m^2/kg^2), m1 and m2 are the masses of the two objects, and r is the distance between their centers.
Plugging in the given values, we get:
F = (6.67 x 10^-11 N*m^2/kg^2) * (13.0 kg * 13.0 kg) / (4.25 m)^2
F = 1.05 x 10^-8 N
Therefore, the magnitude of the gravitational force that one object exerts on the other is 1.05 x 10^-8 N.
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