Asked by Adewunmi
Expand completely (1-12x)^8 in ascending powers of x
Answers
Answered by
oobleck
that will, of course, be
8
∑ C(8,k)(-12x)^(8-k) = 12^8 k^8 - 12(12^6 x^7) + ...
k=0
8
∑ C(8,k)(-12x)^(8-k) = 12^8 k^8 - 12(12^6 x^7) + ...
k=0
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