Let the first term of the G.P be 'a' and the common ratio be 'r'.
We know that the 4th term of the G.P is 1/10, so:
a * r^3 = 1/10
We also know that the 6th term of the G.P is 1/160, so:
a * r^5 = 1/160
Dividing the second equation by the first equation, we get:
r^2 = (1/160) / (1/10)
r^2 = 1/16
r = 1/4 (since r is positive)
Substituting this value of r in the first equation, we get:
a * (1/4)^3 = 1/10
a * 1/64 = 1/10
a = (1/10) * 64
a = 6.4
Therefore, the common ratio is 1/4 and the first term is 6.4.
The 4th and 6th terms of a G.P are 1/10 and 1/160 respectively determine the common ratio and the first term
1 answer
1 answer