Asked by Jamie
List the possible rational roots of 2x^3 + 17x^2 + 23x - 42 = 0
My answer: the possible rational roots are {±1, ±2, ±3, ±6, ±7, ±14, ±21, ±42. ±1/2, ±3/2, ± 7/2, ±21/2}.
Correct?
My answer: the possible rational roots are {±1, ±2, ±3, ±6, ±7, ±14, ±21, ±42. ±1/2, ±3/2, ± 7/2, ±21/2}.
Correct?
Answers
Answered by
Reiny
yes, and guess what?
x = 1 works!
after a quick synthetic division I got
2x^3 + 17x^2 + 23x - 42 = 0
(x-1)(x^2 + 19x + 42) = 0
and that quadratic factors very nicely again.
x = 1 works!
after a quick synthetic division I got
2x^3 + 17x^2 + 23x - 42 = 0
(x-1)(x^2 + 19x + 42) = 0
and that quadratic factors very nicely again.
Answered by
Count Iblis
Yes, this is what you get when you apply the Rational Roots theorem.
But your list is very long, so it is of little use. It is a bit like answering the question by saying that all possible rational roots are the members of Q (as the problem didn't specifically say to list all the roots that the Rational Roots theorem yields).
But your list is very long, so it is of little use. It is a bit like answering the question by saying that all possible rational roots are the members of Q (as the problem didn't specifically say to list all the roots that the Rational Roots theorem yields).
Answered by
Bartolo Windu
Incorrect
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