Asked by will smith
                ) Coordinate point B is at (4,3).  What will the coordinates be for B' after a translation of (x-2,y+3)?
*
B' (5,4)
B' (2,6)
B' (6,2)
B' (-2,3)
What is the coordinate for G(3,-2) after it is reflected across the x-axis?
*
(2,3)
(-2,3)
(3,2)
(-3,-3)
What is the translation rule that describes the result of the composition of
(x, y) --> (x+4, y-1) and (x, y) --> (x-5, y-5)?
*
(x, y) --> (x-1, y-6)
(x, y) --> (x+1, y-3)
(x, y) --> (x+9, y+6)
(x, y) --> (x+1, y+6)
            
        *
B' (5,4)
B' (2,6)
B' (6,2)
B' (-2,3)
What is the coordinate for G(3,-2) after it is reflected across the x-axis?
*
(2,3)
(-2,3)
(3,2)
(-3,-3)
What is the translation rule that describes the result of the composition of
(x, y) --> (x+4, y-1) and (x, y) --> (x-5, y-5)?
*
(x, y) --> (x-1, y-6)
(x, y) --> (x+1, y-3)
(x, y) --> (x+9, y+6)
(x, y) --> (x+1, y+6)
Answers
                    Answered by
            Damon
            
    ) Coordinate point B is at (4,3). What will the coordinates be for B' after a translation of (x-2,y+3)?
4-2 = 2
3+3 = 6
so
(2,6)
*
B' (5,4)
B' (2,6) <---------------------------
B' (6,2)
B' (-2,3)
What is the coordinate for G(3,-2) after it is reflected across the x-axis?
*
3 is unchanged
-2 becomes +2
so
(3 , 2)
(2,3)
(-2,3)
(3,2) <-------------------------
(-3,-3)
What is the translation rule that describes the result of the composition of
(x, y) --> (x+4, y-1) and (x, y) --> (x-5, y-5)?
*
+4 - 5 is -1 and - 1 - 5 = -6
(x, y) --> (x-1, y-6) <--------------------------
(x, y) --> (x+1, y-3)
(x, y) --> (x+9, y+6)
(x, y) --> (x+1, y+6)
    
4-2 = 2
3+3 = 6
so
(2,6)
*
B' (5,4)
B' (2,6) <---------------------------
B' (6,2)
B' (-2,3)
What is the coordinate for G(3,-2) after it is reflected across the x-axis?
*
3 is unchanged
-2 becomes +2
so
(3 , 2)
(2,3)
(-2,3)
(3,2) <-------------------------
(-3,-3)
What is the translation rule that describes the result of the composition of
(x, y) --> (x+4, y-1) and (x, y) --> (x-5, y-5)?
*
+4 - 5 is -1 and - 1 - 5 = -6
(x, y) --> (x-1, y-6) <--------------------------
(x, y) --> (x+1, y-3)
(x, y) --> (x+9, y+6)
(x, y) --> (x+1, y+6)
                    Answered by
            l;
            
    whats the answer
    
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