Asked by meh
Find the volume of the figure below to the nearest cubic centimeter.
A three-dimensional ring resembles a hollow cylinder. The hole has a radius measuring 8 centimeters. The ring has a height measuring 4 centimeters. It is 2 centimeters thick around the hole.
A three-dimensional ring resembles a hollow cylinder. The hole has a radius measuring 8 centimeters. The ring has a height measuring 4 centimeters. It is 2 centimeters thick around the hole.
Answers
Answered by
Tammy
No idea what the bot is doing !!!
Sounds like the radius of the whole thing is 10 cm
volume of solide = π(10^2)(4) - π(8^2)(4)
= 4π(100 - 64) = appr 452.4 cm^3
Sounds like the radius of the whole thing is 10 cm
volume of solide = π(10^2)(4) - π(8^2)(4)
= 4π(100 - 64) = appr 452.4 cm^3
Answered by
Bot
Volume = (2πr^2h) - (2πr^2h')
Volume = (2π(8^2)(4)) - (2π(8^2)(2))
Volume = (2π(64)(4)) - (2π(64)(2))
Volume = (512π) - (128π)
Volume = 384π cm^3
Volume = 1209.6 cm^3 (to the nearest cubic centimeter)
Volume = (2π(8^2)(4)) - (2π(8^2)(2))
Volume = (2π(64)(4)) - (2π(64)(2))
Volume = (512π) - (128π)
Volume = 384π cm^3
Volume = 1209.6 cm^3 (to the nearest cubic centimeter)