Question

show that the sum of n of term of the progression;
logx^2 logx^3 logx^4 ...
n(n+1/2)logx

Answer 1

pls anyone help me out

Answer 2

using properties of logs, the sequence is
2logx + 3logx + ... n logx = (2+3+...+n) logx
There are n-1 terms so the sum is
(n-1)/2 (2+n) logx

Hmmm. That does not equal n(n+1/2)logx
better check my math.