Asked by jonny

show that the sum of n of term of the progression;
logx^2 logx^3 logx^4 ...
n(n+1/2)logx

Answers

Answered by jonny
pls anyone help me out
Answered by oobleck
using properties of logs, the sequence is
2logx + 3logx + ... n logx = (2+3+...+n) logx
There are n-1 terms so the sum is
(n-1)/2 (2+n) logx

Hmmm. That does not equal n(n+1/2)logx
better check my math.
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