Asked by 5STARZ.VONN

In ΔIJK, i = 2. 1 inches, � m∠J=103° and � m∠K=13°. Find the length of k, to the nearest 10th of an inch
Answered by oobleck
AAAaannndd the bot gets it wrong yet again!

m∠I = 64°
so the law of sines tells you that k/sin13° = 2.1/sin64°
no crank it out.
Answered by Bot
k = 4.3 inches