Question

Which of the following are true about railroad expansion in the late 19th century? Choose all that apply.

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Answered by **** connexus
Which of the following are true about railroad expansion in the late 19th century? Choose all that apply.
A. it led to new managerial forms and techniques.
B. it accelerated the growth of new territories.
C. it was financed by the government.
D. it grew to quickly and large corporations lost money.
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why did miners in the west create groups of vigilantes?
A. to clear forests and prepare for mining.
B. to take control of claims from businesses.
C. to enforce laws and punish criminals.
D. to replace independent contractors.
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which U.S. region was most impacted by the completion transcontinental railroad in 1869?
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why did railroad leaders consolidate their lines in the 1880's?
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can you simplify?
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which of the following was an effect of the discovery of gold and silver on western development/
A. it caused a sharp decrease in the population of cities
B. there was no longer a need for the railroad
C. the value of gold and silver decreased
D. it contributed to the opening of the west frontier
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you flip a cion 30 times and get heads 11 times so the probability of getting heads is 11/30 is this an example of experimental or theoretical probability?
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if you have made 3 out of 10 free throws how many can you expect to make if you shoot 100 free throws.
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what is the probability that a month picked at random will have 31 days
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if you rolled a number cube 100 times how many times could you expect to roll an even number
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a bag holds 2 yellow, 1 green, 2 red marbles if you were to draw a marble from the bag 150 times, and replace it after each draw how many yellows would you expect to get
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a bag has 6 green marbles, 4 red marbles, 5 yellow marbles, and three purple marbles. what is the probability of choosing a purple marble?
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you roll a pair of numbered dice and then flip a coin is this an example of dependent or independent events?
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there are five different cookies in a bag one of them is your favorite, what are the chances you do not get your favorite?
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a basket contains 5 green lollipops, 12 red lollipops, and 7 orange lollipops, when a lollipop is taken from the basket it is not replaced. what is the probability of getting orange then orange
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a basket contains 5 green lollipops, 12 red lollipops, and 7 orange lollipops, when a lollipop is taken from the basket it is not replaced. what is the probability of getting orange then orange.
Please give the answer in fraction form.
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the letters in the word Paris are written on slips of paper and then put in a basket each letter will be put back after its drawn what is P(r, then vowel)
Answer
WHAT IS WITH THE BOTSSSSSSSSSSSSSS
Answered by Bot
A. It increased the speed of transportation.
B. It increased the cost of transportation.
C. It increased the number of jobs available.
D. It increased the number of people who could travel.

A. It increased the speed of transportation.
C. It increased the number of jobs available.
D. It increased the number of people who could travel.
Answered by Bot
A. it led to new managerial forms and techniques.
B. it accelerated the growth of new territories.
Answered by Bot
C. to enforce laws and punish criminals.
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The West was the U.S. region that was most impacted by the completion of the transcontinental railroad in 1869.
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Railroad leaders consolidated their lines in the 1880s to eliminate competition, eliminate duplicative routes, reduce waste, and increase efficiency. Consolidation also allowed for greater control over prices and transportation rates, which could be used to drive smaller companies out of business and further increase the power and influence of the larger, consolidated companies. This consolidation was a major step in the development of the modern corporate economy in the United States.
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In the 1880s, railroad leaders combined their separate lines into larger, more efficient companies to eliminate competition and reduce costs. This helped them exert greater control over prices and transportation rates, and gain more power in the economy. The consolidation of railroads played a big role in the development of modern corporations in the US.
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D. it contributed to the opening of the west frontier.
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This is an example of experimental probability. Theoretical probability is based on the mathematical analysis of all possible outcomes, while experimental probability is based on actual trials or experiments. Since the probability of getting heads in this scenario is determined through actual trials, it is an example of experimental probability.
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We can use proportions to estimate how many free throws you can expect to make.

If you have made 3 out of 10 free throws, that means your free throw success rate is 3/10 or 0.3.

We can use this success rate to estimate how many free throws you can expect to make out of 100:

Expected free throws made = (0.3) x 100 = 30

Therefore, if you shoot 100 free throws, based on your success rate so far, you can expect to make 30 of them.
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There are 12 months in a year, of which 7 have 31 days (January, March, May, July, August, October and December), and 5 have 30 days (April, June, September, November) and February has 28 or 29 days depending upon whether it is a leap year or not.

So the probability that a month picked at random will have 31 days is:

Number of months with 31 days / Total number of months

= 7 / 12

= 0.583 or approximately 58.3%

Therefore, there is a 58.3% chance that a month picked at random will have 31 days.
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A number cube has 6 sides numbered from 1 to 6, with three even numbers (2, 4, and 6) and three odd numbers (1, 3, and 5).

The probability of rolling an even number on one roll is 3/6 = 1/2.

If you roll the number cube 100 times, you can expect to roll an even number approximately (1/2) * 100 = 50 times.

Therefore, if you rolled a number cube 100 times, you could expect to roll an even number approximately 50 times.
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There are 5 marbles in the bag, of which 2 are yellow.

The probability of drawing a yellow marble on one draw is:

Number of yellow marbles / Total number of marbles

= 2/5

If you draw from the bag 150 times, each time replacing the marble after the draw, you would expect to draw a yellow marble approximately:

Expected number of yellows = (2/5) x 150

Expected number of yellows = 60

Therefore, if you drew a marble from the bag 150 times, replacing it after each draw, you could expect to get 60 yellow marbles (on average).
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The probability of choosing a purple marble from the bag is:

Number of purple marbles / Total number of marbles

= 3 / (6 + 4 + 5 + 3)

= 3/18

= 1/6

Therefore, the probability of choosing a purple marble is 1/6 or approximately 0.167 (rounded to three decimal places).
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This is an example of independent events.

The outcome of rolling the pair of numbered dice does not affect the outcome of flipping the coin, and the outcome of flipping the coin does not affect the outcome of rolling the dice. Therefore, the two events are independent of each other. The result of one event does not affect the probability of the other event occurring.
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If there are five different cookies in a bag and one of them is your favorite, then there are four cookies that are not your favorite.

The probability of not getting your favorite cookie is the same as the probability of choosing one of the four cookies that are not your favorite:

Probability of not getting your favorite = Number of cookies that are not your favorite / Total number of cookies

Probability of not getting your favorite = 4 / 5

Probability of not getting your favorite = 0.8 or 80%

Therefore, the chances of not getting your favorite cookie is 80%.
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When the first lollipop is taken from the basket, there are a total of 24 lollipops left (since it is not replaced). Of those 24 lollipops, 6 are orange.

The probability of getting an orange lollipop on the first draw is therefore:

P(orange on first draw) = 7/24

After taking one lollipop out, there are 23 lollipops left in the basket, of which 5 are green and 5 are orange.

The probability of getting an orange lollipop on the second draw (assuming an orange lollipop was drawn on the first draw and not replaced) is therefore:

P(orange on second draw, given orange on first draw) = 5/23

The probability of getting "orange then orange" is the product of these two probabilities:

P(orange then orange) = P(orange on first draw) * P(orange on second draw, given orange on first draw)

P(orange then orange) = (7/24) * (5/23)

P(orange then orange) = 0.0797 or approximately 0.08

Therefore, the probability of picking an orange lollipop and then another orange lollipop (without replacement) is approximately 0.08 or 8%.
Answered by Bot
When the first lollipop is taken from the basket, there are a total of 24 lollipops left (since it is not replaced). Of those 24 lollipops, 6 are orange.

The probability of getting an orange lollipop on the first draw is therefore:

P(orange on first draw) = 7/24

After taking one lollipop out, there are 23 lollipops left in the basket, of which 5 are green and 5 are orange.

The probability of getting an orange lollipop on the second draw (assuming an orange lollipop was drawn on the first draw and not replaced) is therefore:

P(orange on second draw, given orange on first draw) = 5/23

The probability of getting "orange then orange" is the product of these two probabilities:

P(orange then orange) = P(orange on first draw) * P(orange on second draw, given orange on first draw)

P(orange then orange) = (7/24) * (5/23)

P(orange then orange) = 35/552

Therefore, the probability of picking an orange lollipop and then another orange lollipop (without replacement) is 35/552.
Answered by Bot
The letters in the word Paris are {P, a, r, i, s}.

If each letter is put back after it is drawn, then the probability of drawing a particular letter is always the same (i.e., the letters are replaced).

Since there is one "r" in the word "Paris" and a total of 5 letters, the probability of drawing an "r" on the first draw is 1/5.

Once the "r" is put back in the basket, there are now four letters remaining, of which two are vowels ("a" and "i"). Therefore, the probability of drawing a vowel on the second draw (given that an "r" was drawn on the first draw and replaced) is 2/4 or 1/2.

The probability of drawing an "r" on the first draw and then a vowel on the second draw is the product of these two probabilities:

P(r, then vowel) = P(r) * P(vowel | r)

P(r, then vowel) = (1/5) * (1/2)

P(r, then vowel) = 1/10

Therefore, the probability of drawing an "r" on the first draw and then a vowel on the second draw (with replacement) is 1/10.
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