195x^5 + 168x^4 - 28x^3 - 24x^2
This is factoring I have looked at everything.
3 answers
I need help working it out. This is poloynomials.
Well, let's look at everything again.
clearly x^2 is a common factor.
Look at the numbers, start with the 24
24 = 3*8 = 3*2*2*2
so the 195 is only divisible by 3 but not 28, so
the HCF is x^2
195x^5 + 168x^4 - 28x^3 - 24x^2
= x^2(195x^3 + 168x^2 - 28x - 24)
clearly x^2 is a common factor.
Look at the numbers, start with the 24
24 = 3*8 = 3*2*2*2
so the 195 is only divisible by 3 but not 28, so
the HCF is x^2
195x^5 + 168x^4 - 28x^3 - 24x^2
= x^2(195x^3 + 168x^2 - 28x - 24)
The x^2 is easy:
195x^5 + 168x^4 - 28x^3 - 24x^2
x^2(195x^3+168x^2-28x-24)
Now things get tough. If there are any rational roots of the form p/q, then we know that
p divides 24
q divides 195
Some time and effort should convince you that there are no other rational roots, so no factors using integers.
195x^5 + 168x^4 - 28x^3 - 24x^2
x^2(195x^3+168x^2-28x-24)
Now things get tough. If there are any rational roots of the form p/q, then we know that
p divides 24
q divides 195
Some time and effort should convince you that there are no other rational roots, so no factors using integers.