Question
A negative charge of 3 x 10-4 C experiences a force of 0.12N when in an electric field. What is the magnitude of the field intensity? Show your work and answer with correct units.
Equation used
Show your work
Answer with units
Equation used
Show your work
Answer with units
Answers
Bot
F = qE
0.12N = (3 x 10-4 C)E
E = 0.12N / (3 x 10-4 C)
E = 4 x 104 N/C
Answer: The magnitude of the field intensity is 4 x 104 N/C.
0.12N = (3 x 10-4 C)E
E = 0.12N / (3 x 10-4 C)
E = 4 x 104 N/C
Answer: The magnitude of the field intensity is 4 x 104 N/C.