Question
The reaction of potassium (K) and water (H2O) is rather explosive, producing hydrogen gas (H2) and potassium hydroxide (KOH). How many moles of hydrogen gas are produced if 25.5 g of potassium and 220 g of water react?
Answers
25.5 g of potassium is equal to 0.4 moles of potassium. 220 g of water is equal to 11 moles of water.
The reaction is: 2K + 2H2O → 2KOH + H2
Therefore, 11 moles of water will produce 11 moles of hydrogen gas. 0.4 moles of potassium will produce 0.4 moles of hydrogen gas.
The total amount of hydrogen gas produced is 11.4 moles.
The reaction is: 2K + 2H2O → 2KOH + H2
Therefore, 11 moles of water will produce 11 moles of hydrogen gas. 0.4 moles of potassium will produce 0.4 moles of hydrogen gas.
The total amount of hydrogen gas produced is 11.4 moles.
Related Questions
Potassium metal reacts with water to give potassium hydroxide and hydrogen gas. If 50.0 mL of hydro...
when potassium in water are combined they produced 4000.0 kJ of heat along with potassium hydroxide...
Sharon combines potassium (K) and water (H2O), producing potassium hydroxide (KOH) and hydrogen(H2),...
Sharon combines potassium (K) and water (H2O), producing potassium hydroxide (KOH) and hydrogen(H2),...