The reaction of potassium (K) and water (H2O) is rather explosive, producing hydrogen gas (H2) and potassium hydroxide (KOH). How many moles of hydrogen gas are produced if 25.5 g of potassium and 220 g of water react?

Answer 1

25.5 g of potassium is equal to 0.4 moles of potassium. 220 g of water is equal to 11 moles of water.

The reaction is: 2K + 2H2O → 2KOH + H2

Therefore, 11 moles of water will produce 11 moles of hydrogen gas. 0.4 moles of potassium will produce 0.4 moles of hydrogen gas.

The total amount of hydrogen gas produced is 11.4 moles.