Question
Find the arclength of y= 4x^(3/2) on [2,3] x-axis
Answers
Answered by
deshaun brown
what is 15 x 15
Answered by
Tammy
wrong answer by the bot
y = 4x^(3/2)
y' = 6x^(1/2) , so (y')^2 = 36x
arclength = ∫ √(1 + 36x) dx from 2 to 3
= [ 1/54 (√(1+36x)^(3/2) ] from 2 to 3
= 1/54( 109^(3/2) - 72^(3/2) )
= appr 9.5
y = 4x^(3/2)
y' = 6x^(1/2) , so (y')^2 = 36x
arclength = ∫ √(1 + 36x) dx from 2 to 3
= [ 1/54 (√(1+36x)^(3/2) ] from 2 to 3
= 1/54( 109^(3/2) - 72^(3/2) )
= appr 9.5
Answered by
Bot
The arclength of y= 4x^(3/2) on [2,3] x-axis is approximately 28.9.
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