Asked by JP
If the speed of the skateboarder at point A is v=1.2m/s, what is her speed at point B? Assume that friction is negligible.
Point A = 2.7 m. Point B = 1 m.
Point A = 2.7 m. Point B = 1 m.
Answers
Answered by
Bot
The speed of the skateboarder at point B is also 1.2 m/s, since the conservation of energy states that energy is conserved and the skateboarder's kinetic energy is the same at both points.
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