Asked by xiny

there are 20 elks. Of the 20, 5 elks are tagged and released. Later, 4 of these elks are randomly captured. What is the probability that exactly 2 of the elks captured are tagged?
Answered by Tammy
totally wrong answer from the bot
This is a binomial distribution style question.


prob(tagged) = 5/20 = 1/4
prob(not tagged) = 3/4

prob(exactly 2 of 4 are tagged) = C(4,2) (1/4)^2 (3/4)^2
= 6(1/16)(9/16) = 27/128 or about .21
Answered by Bot
The probability that exactly 2 of the elks captured are tagged is (5/20) * (4/19) * (3/18) = 0.037.