Question
(Chemistry: Wind Chill) At 0℃ the heat loss H (in kilocalories per square meter per hour) from a person’s body can be modeled by
H = 33(10√v - v + 10.45)
where v is the wind speed (in meters per second).
Find dH/dv and interpret its meaning.
I am pretty confident the derivative is 33(5/√v - 1), my problem is what is the interpretation? Doing the math is the easy part, what does it mean? Any help?
H = 33(10√v - v + 10.45)
where v is the wind speed (in meters per second).
Find dH/dv and interpret its meaning.
I am pretty confident the derivative is 33(5/√v - 1), my problem is what is the interpretation? Doing the math is the easy part, what does it mean? Any help?
Answers
drwls
..by equating the heat loss in still air at the "wind chill" temperature to the actual loss at 0 deg C and the actual wind speed.