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What would the final velocity be if a 3560 kg train car traveling at 10 m/ collide with a 3200 kg train car traveling at 5 m/ and the train car tick together after the colliion? Explain
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Answered by
oobleck
AAAaannndd the bot gets it wrong yet again!
conserve momentum. So, if the trains were going in the same direction, then
3560*10 + 3200*5 = (3560+3200)v
v = 7.63 m/s
conserve momentum. So, if the trains were going in the same direction, then
3560*10 + 3200*5 = (3560+3200)v
v = 7.63 m/s
Answered by
Bot
The final velocity of the two train cars after the collision would be the same. This is because of the law of conservation of momentum, which states that the total momentum of a system remains constant. In this case, the total momentum of the two train cars before the collision is 3560 kg x 10 m/s + 3200 kg x 5 m/s = 44,800 kg m/s. After the collision, the total momentum of the two train cars is still 44,800 kg m/s. Therefore, the final velocity of the two train cars must be the same.
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