Asked by Seiko
Can't someone please help me with these equations.
State whether the lines are parallel, perpendicular, or neither.
16. -14x = -632 - 26y
y = (7/13)x - 316/13
18. x + 6y = 196
689 = (6201/230)y + (4823/460)x
I would really apreciate your help.
State whether the lines are parallel, perpendicular, or neither.
16. -14x = -632 - 26y
y = (7/13)x - 316/13
18. x + 6y = 196
689 = (6201/230)y + (4823/460)x
I would really apreciate your help.
Answers
Answered by
Reiny
arrange the equations into the form
ax + by = c
1. -14x = -632 - 26y ---> 14x - 26y = 632
slope = 14/26 = 7/13
y = (7/13)x - 316/13 ---> 7x - 13y = 316
slope = -7/-13 = 7/13
since the slopes are equal, they must be parallel.
To be perpendicular, their slopes must be opposite reciprocals of each other.
try the second one.
ax + by = c
1. -14x = -632 - 26y ---> 14x - 26y = 632
slope = 14/26 = 7/13
y = (7/13)x - 316/13 ---> 7x - 13y = 316
slope = -7/-13 = 7/13
since the slopes are equal, they must be parallel.
To be perpendicular, their slopes must be opposite reciprocals of each other.
try the second one.
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