V varies as partly as q and partly as q square.when v=34,q=2 and when v=190 q=5

Answer 1

The equation is: V = kq + kq^2

Substituting the given values, we get:

34 = k(2) + k(2)^2
190 = k(5) + k(5)^2

Solving the two equations, we get:

k = 6

Answer 2

Mr. bot, basic concept here: you can't use the same parameter !!

V = kq + mq^2
case 1: v=34,q=2
34 = 2k + 4m ,#1
case 2: v=190 q=5
190 = 5k + 25m , #2

#1 by 5 ---> 170 = 10k + 20m
#2 by 2 ---> 380 = 10k + 50m
subtract
210 = 30m
m = 7
sub into #1,
34 = 2k + 28
2k = 6
k = 3

V = 3q + 7q^2