Question

What is the solubility of silver chloride in water at 25C? (Ksp = 1.6 x 10^-10)

I don't know how to do the work

AgCl(s) ==> Ag^+ + Cl^-
Let x = molar solutility of AgCl.
Then x = molar concentration of Ag^+.
and x = molar concentraton of Cl^-
Then Ksp = (Ag^+)(Cl^-) = 1.6E-10
Substitute from above.
x*x=1.6E-10
Solve for x. That is molar solubility in mols/L. If you want grams AgCl, then M x molar mass = grams.

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