Question
Solve for x.
(l is the absoulte bar, not one)
3*l 3x-2 l -6 > l 3x-2 l
We're given;
3*|3x-2|-6 >|3x-2|
Add -|3x-2| to both sides to get
2*|3x-2|-6 >0
Add 6 to both sides to get
2*|3x-2|>6
Divide both sides by 2
|3x-2|>3
This means 3x-2>3 or 3x-2<-3
3x-2>3 means 3x > 5 or x > 5/3
3x-2<-3 means 3x < -1 or x < -1/3
Be sure to test some values to verify this.
(l is the absoulte bar, not one)
3*l 3x-2 l -6 > l 3x-2 l
We're given;
3*|3x-2|-6 >|3x-2|
Add -|3x-2| to both sides to get
2*|3x-2|-6 >0
Add 6 to both sides to get
2*|3x-2|>6
Divide both sides by 2
|3x-2|>3
This means 3x-2>3 or 3x-2<-3
3x-2>3 means 3x > 5 or x > 5/3
3x-2<-3 means 3x < -1 or x < -1/3
Be sure to test some values to verify this.