The equation of the perpendicular bisector of AC is the line that passes through the midpoint of AC and is perpendicular to AC.
The midpoint of AC is (7, -3).
The slope of AC is -6/14.
The slope of the perpendicular bisector of AC is 14/6.
Therefore, the equation of the perpendicular bisector of AC in point slope form is y - (-3) = (14/6)(x - 7).
Given ABC with A(-4,-2), B(4,4) and C(18,-8) answer the question
write the equation for line containing perpendicular bisector of AC in point slope form, show work.
3 answers
AAAaannndd the bot gets it wrong yet again!
The midpoint of AC is (7,-5)
The slope of AC is -3/11 so the slope of the perp. is 11/3
y+5 = 11/3 (x-7)
The midpoint of AC is (7,-5)
The slope of AC is -3/11 so the slope of the perp. is 11/3
y+5 = 11/3 (x-7)
The question is totally messed up by the bot ....
correction by a human:
midpoint of AC = (7,-5)
slope AC = (-8+2)/(18+4) = -6/22 = -3/11
slope of perpendicular bisector = 11/3
equation:
y + 5 = (11/3(x - 7)
correction by a human:
midpoint of AC = (7,-5)
slope AC = (-8+2)/(18+4) = -6/22 = -3/11
slope of perpendicular bisector = 11/3
equation:
y + 5 = (11/3(x - 7)