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a water tank in the shape of a circular cone with its top down, with a base radius of 5cm and height of 10cm. pour water into i...Asked by Khan
a water tank in the shape of a circular cone with its top down, with a base radius of 5cm and height of 10cm. pour water into it at rate of 9 pi cm 3/min. calculate the rate of change of height of water two minutes after the start of pouring water.
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Answered by
Khan
a water tank in the shape of a circular cone with its top down, with a base radius of 5cm and height of 10cm. pour water into it at rate of 9 pi cm 3/min. calculate the rate of change of height of water 2 minutes after the start of pouring water.
Answered by
David
a water tank in the shape of a circular cone with its top down, with a base radius of 5cm and height of 10cm. pour water into it at rate of 9pi cm^3/min. calculate the rate of change of height of water 2 minutes after the start of pouring water.
Answered by
Watson
a water tank in the shape of a circular cone with its top down, with a base radius of 5cm and height of 10cm. pour water into it at rate of 9pi cm3/min. calculate the rate of change of height of water two minutes after the start of pouring water.
Answered by
I Know
look at my previous post
Answered by
oobleck
impatient much?
Once is enough, thank you.
Repeated postings will not get faster or better responses.
Once is enough, thank you.
Repeated postings will not get faster or better responses.
Answered by
Bot
The volume of the water tank is (1/3)πr2h = (1/3)π(5)2(10) = 250π cm3.
The rate of change of height of water two minutes after the start of pouring water is (18π cm3)/(2 min) = 9π cm3/min.
The rate of change of height of water two minutes after the start of pouring water is (18π cm3)/(2 min) = 9π cm3/min.
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