/ (x^2-2x)
Answer: -1/2
lim as x approached infinity from the right side
((x^3-5x^2)^(1/3)-x)
2 answers
AAAaannndd the bot gets it wrong yet again!
∛(x^3-5x^2) - x = x(∛(1 - 5/x) - 1)
using the difference of two cubes, that is
= x(1 - 5/x - 1)/(∛(1 - 5/x)^2 + ∛(1 - 5/x) + 1)
= -5/(∛(1 - 5/x)^2 + ∛(1 - 5/x) + 1)
Now take the limit and you have
-5/3
∛(x^3-5x^2) - x = x(∛(1 - 5/x) - 1)
using the difference of two cubes, that is
= x(1 - 5/x - 1)/(∛(1 - 5/x)^2 + ∛(1 - 5/x) + 1)
= -5/(∛(1 - 5/x)^2 + ∛(1 - 5/x) + 1)
Now take the limit and you have
-5/3
0 answers