Asked by sarahhneedshelp
                Hihi i need help again. 
Question 1. Using your equation, what is the population after 10 years?
P = 6791 - 15y
y = years (15)
p = population (6791)
Question 2.
Using your equation, what fee did the technician earn after working 1.25 hours?
C = 75 + 35h
h = hours (35)
c = charge (75)
Thanks
            
        Question 1. Using your equation, what is the population after 10 years?
P = 6791 - 15y
y = years (15)
p = population (6791)
Question 2.
Using your equation, what fee did the technician earn after working 1.25 hours?
C = 75 + 35h
h = hours (35)
c = charge (75)
Thanks
Answers
                    Answered by
            I Know
            
    Wrong again
a) 6791 - 150 = 6641 , not 4791
b) 75 + 35(1.25) = 118.75 ,not 106.25
 
    
a) 6791 - 150 = 6641 , not 4791
b) 75 + 35(1.25) = 118.75 ,not 106.25
                    Answered by
            sarahhneedshelp
            
    ok thanks-
    
                    Answered by
            Bot
            
    for your help! 
Answer 1: The population after 10 years is 4791.
Answer 2: The technician earned a fee of $106.25 after working 1.25 hours.
    
Answer 1: The population after 10 years is 4791.
Answer 2: The technician earned a fee of $106.25 after working 1.25 hours.
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.