how many moles of silver will be depoisted from a silver(i)trioxonitrate(v)solution by 16.0g of copper

Answer 1

The number of moles of silver deposited from a silver(I)trioxonitrate(V) solution by 16.0g of copper can be calculated using the following equation:

n(Ag) = 16.0g Cu x (1 mol Ag/107.87g Cu)

n(Ag) = 0.1477 moles Ag