Asked by INeedThatA$AP,NoRocky
What is the inverse of f(x)=4−x−−−−−√3−2?
f−1(x)=4−(x+2)3
f−1(x)=x3+2
f−1(x)=4+(x−2)3
f−1(x)=(x+2)3−4
f−1(x)=4−(x+2)3
f−1(x)=x3+2
f−1(x)=4+(x−2)3
f−1(x)=(x+2)3−4
Answers
Answered by
oobleck
If you meant f(x) = 4-∛(x-2) then
f<sup><sup>-1</sup></sup>(x) = (4-x)^3 + 2
If not, then maybe you can write it more clearly.
Just use cbroot(exp) for the cube root of (exp)
f<sup><sup>-1</sup></sup>(x) = (4-x)^3 + 2
If not, then maybe you can write it more clearly.
Just use cbroot(exp) for the cube root of (exp)
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