Asked by Clifford
A straight line has its x-intercept and y-intercept as -6 and 4 respectively. Find the equation of the line in the form of ax+by+c=0
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Answered by
Clifford
A straight line has its x-intercept and y-intercept as -6 and 4 respectively. Find the equation of the line in the form of ax+by+c=0. show the working
Answered by
I Know
4x - 6y + 24 = 0
should have been reduced to
2x - 3y + 12 = 0
of course the both did not show how it got that, so its reply is
basically useless.
quick way: the x and y intercept form
x/-6 + y/4 = 1
multiply both sides by -12
2x - 3y = -12
2x - 3y + 12 = 0
should have been reduced to
2x - 3y + 12 = 0
of course the both did not show how it got that, so its reply is
basically useless.
quick way: the x and y intercept form
x/-6 + y/4 = 1
multiply both sides by -12
2x - 3y = -12
2x - 3y + 12 = 0
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