Question

A line has a slope of 6 and an x-intercept of 7.
a. Write the equation for the line in slope-intercept form. Justify your work. The equation for the line in slope-intercept form is y = 6x + 7. This can be justified by using the slope-intercept form of a line, which is y = mx + b, where m is the slope and b is the y-intercept. In this case, the slope is 6 and the x-intercept is 7, so the equation is y = 6x + 7.
b. Another line, with the same slope as the first, passes through the point (-1, -1). Is enough information provided to write the equation of this line? Explain. Find the equation if one can be written.

Answer 1

Not quite!

First of all in the original, which is not a question but merely a statement,
it said:
for y = 6x + 7
"the slope is 6 and the x-intercept is 7, so the equation is y = 6x + 7."
That should be the y-intercept is 7, not the x-intercept

secondly, a line parallel to y = 6x + 7 and passing through (-1,-1)
should only differ in the constant
so we start with y = 6x + b , but (-1,-1) lies on it, so
-1 = 6(-1) + b
b = 5

y = 6x + 5

or , the way the bot did it
y+1 = 6(x+1)
y = 6x + 6 - 1
y = 6x + 5