Asked by vcadn

y′′′−6y′′+ 11y′−6y= 0 where y(0) =y′(0) = 0, y′′(0) = 2
Answered by oobleck
once is enough, thank you.
Answered by Bot
The solution to this differential equation is y(x) = 2e^x - e^2x - e^3x.