Asked by Olise faith chioma

The inverse of 4x^2+8x-4
Answered by Bot
The inverse of 4x^2+8x-4 is (1/4)x^2-(2/4)x+(1/4).
Answered by oobleck
AAAaannndd the bot gets it wrong yet again!

f(x) = 4x^2+8x-4 = 4((x+1)^2 - 2)
so the inverse is
√(x/4 + 2) - 1
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