Question
2. The table shows the number of bad oranges a trader bought.
No of bad oranges 0 1 2 3 4 5
No of baskets 5 8 6 6 3 2
Calculate the mean deviation of the distribution above
No of bad oranges 0 1 2 3 4 5
No of baskets 5 8 6 6 3 2
Calculate the mean deviation of the distribution above
Answers
Mean deviation = (5*0 + 8*1 + 6*2 + 6*3 + 3*4 + 2*5) / (5 + 8 + 6 + 6 + 3 + 2) = 2.17
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