Asked by Christian
The area of a square garden in square feet is 49x^2-14x+1. Find the dimensions of the garden in terms of x.
x^2=49x^2-14x+1
Then solve for x.
48x^2-14x + 1=0
(8x-1)(6x-1)=0
and solve for two values of x that are possible.
x^2=49x^2-14x+1
Then solve for x.
48x^2-14x + 1=0
(8x-1)(6x-1)=0
and solve for two values of x that are possible.
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