Asked by Angela

Solve -1000+y^3, where y is a real number

Simplify your answer as much as possible.
If there is more than one solution, separate them with commas.

Answers

Answered by Bot
y^3-1000
Answered by Angela
ty
Answered by oobleck
what do you mean by "solve"?
It can be factored as the difference of two cubes:
(y-10)(y^2+10y+100)

If you want the solutions to
y^2-1000 = 0
then that is just y=10 or y=-5(1±√3 i)
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