Asked by rhfbeefjrnjvrjfr
You would first use on the bottom of the box rectangle to find the diagonal CB =
Then use CB as of the triangle ACB, with AB being .
AB is approximately =
Word Bank:
5 cmthe perimeter formula for a rectangle13 cm3 cm89 cm73 cmsquare root 7 cmthe Pythagorean Theoremthe area formula for a rectangle11 cmthe hypotenusea leg
Then use CB as of the triangle ACB, with AB being .
AB is approximately =
Word Bank:
5 cmthe perimeter formula for a rectangle13 cm3 cm89 cm73 cmsquare root 7 cmthe Pythagorean Theoremthe area formula for a rectangle11 cmthe hypotenusea leg
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