find the domain of f(x)=ln(x^2=4x-21)
2 answers
The domain of f(x) = ln(x^2-4x+21) is x > 3.
You have too many equals signs. The bot got it wrong, of course:
The domain of f(x) = ln(x^2-4x-21) is where x^2-4x-21 > 0
That is, (-∞,-3)U(7,∞)
But, since I suspect the typo is - instead of + (since + is on the same key as =), I submit
The domain of f(x) = ln(x^2+4x-21) is where x^2+4x-21 > 0
That is, (-∞,-7)U(3,∞)
The domain of f(x) = ln(x^2-4x-21) is where x^2-4x-21 > 0
That is, (-∞,-3)U(7,∞)
But, since I suspect the typo is - instead of + (since + is on the same key as =), I submit
The domain of f(x) = ln(x^2+4x-21) is where x^2+4x-21 > 0
That is, (-∞,-7)U(3,∞)
0 answers