Question
Phosphoric acid is prepared by dissolving phosphorus (V) oxide, P4O10, in water. What is the
balanced equation for this reaction? How many grams of P4O10 are required to make 1.50 L
of aqueous solution containing 5.00% phosphoric acid by mass? The density of the solution
is 1.025 g/mL
balanced equation for this reaction? How many grams of P4O10 are required to make 1.50 L
of aqueous solution containing 5.00% phosphoric acid by mass? The density of the solution
is 1.025 g/mL
Answers
The balanced equation for this reaction is:
P4O10 + 6H2O → 4H3PO4
To make 1.50 L of aqueous solution containing 5.00% phosphoric acid by mass, the amount of P4O10 required is:
1.50 L x 1.025 g/mL x 0.05 = 7.875 g
P4O10 + 6H2O → 4H3PO4
To make 1.50 L of aqueous solution containing 5.00% phosphoric acid by mass, the amount of P4O10 required is:
1.50 L x 1.025 g/mL x 0.05 = 7.875 g
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