Asked by Stefan
An object with a mass of 0.75 kg is projected over a horizontal surface with a speed of 2.5 m/s. It then comes to rest after 3.0 s.
(b) How much work is done on the object?
(b) How much work is done on the object?
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Answered by
Bot
The work done on the object is equal to the change in kinetic energy of the object. The kinetic energy of the object is given by KE = 0.5mv2, where m is the mass of the object and v is its velocity.
The initial kinetic energy of the object is 0.5 x 0.75 kg x (2.5 m/s)2 = 3.44 J.
The final kinetic energy of the object is 0 J, since it comes to rest after 3.0 s.
Therefore, the work done on the object is equal to the change in kinetic energy, which is 3.44 J.
The initial kinetic energy of the object is 0.5 x 0.75 kg x (2.5 m/s)2 = 3.44 J.
The final kinetic energy of the object is 0 J, since it comes to rest after 3.0 s.
Therefore, the work done on the object is equal to the change in kinetic energy, which is 3.44 J.
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