Asked by Stefan
An object with a mass of 5.13 kg is placed on top of a spring and compresses the spring by 0.25 m. (a) What is the force constant of the spring? (b) How high will this object go when the spring releases its energy?
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(a) The force constant of the spring can be calculated using the equation F = kx, where F is the force, k is the force constant, and x is the displacement. In this case, F = 5.13 kg x 9.8 m/s2 = 50.6 N and x = 0.25 m. Therefore, the force constant of the spring is k = 50.6 N/0.25 m = 202.4 N/m.
(b) The height to which the object will rise when the spring releases its energy can be calculated using the equation h = (1/2)kx2, where h is the height, k is the force constant, and x is the displacement. In this case, h = (1/2) x 202.4 N/m x (0.25 m)2 = 1.26 m. Therefore, the object will rise to a height of 1.26 m when the spring releases its energy.
(b) The height to which the object will rise when the spring releases its energy can be calculated using the equation h = (1/2)kx2, where h is the height, k is the force constant, and x is the displacement. In this case, h = (1/2) x 202.4 N/m x (0.25 m)2 = 1.26 m. Therefore, the object will rise to a height of 1.26 m when the spring releases its energy.
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